The first cyclist covers a distance of 15km/h x 1h = 15km from 7:00am to 8:00am.
So the distance between Little and Kakamega is reduced to 70km - 15km = 55km.
When they meet, the second cyclist has covered a distance of x km (where x is the distance from Kakamega to the meeting point) in 0.5 hours.
The total time taken for the second cyclist to reach the meeting point is (8:00am - 7:00am) + 0.5 hours = 1.5 hours.
Using the formula: distance = speed x time,
distance covered by the second cyclist = x km
time taken by the second cyclist = 0.5 hours + 1 hour = 1.5 hours
speed of the second cyclist = distance / time = x km / 1.5 hours
Now, we need to find the value of x.
Since both cyclists cover the same distance when they meet, we have:
distance covered by first cyclist = distance covered by second cyclist
15km + x = 55km - x
2x = 40km
x = 20km
Therefore, the speed of the second cyclist is:
speed = distance / time = 20km / 1.5 hours = 13.3 km/h. Answer: \boxed{13.3}.
A cyclist travelling at 15km/h left little at7:00amfor kakamega,a distance of 70km/h .another cyclist left kakamega for little at8:00am.if they met after a half hours,find the speed of the second cyclist?
1 answer