y=2x^2+7x+c
5=4x+7, so x = -1/2
y(-1/2) = -3+c
at x = -1/2, y=2x = -1, so
-1 = -3+c
c=2
y = 2x^2+7x+2
P=(-1/2,-1)
a curve is such that dy/dx=4x+7. the line y=2x meets the curve at point 'P'. Given that the gradient of the curve at P is 5. State the coordinates of P.
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