Wc = mg = 562 N. = Weight of crate.
Fc = 562 N. @30 Deg. = Force of crate.
Fp = 562*sin30 = 281 N. = Force parallel to plane.
Fv = 562*cos30 = 487 N. = Force perpendicular to plane.
a crate weighing 562 newtons is resting on an inclined plane 30 degress above the horizontal. Find the components of the weight forces that are parallel and perpendicular to the plane?
5 answers
270-30=240
a crate weighing 562 newtons is resting on an inclined plane 30 degress above the horizontal. Find the components of the weight forces that are parallel and perpendicular to the plane?
Fgx= 562cos(30.0)=486N
Fly= 562sin(30.0)=281
Tan-1(281 divides 486)
Fly= 562sin(30.0)=281
Tan-1(281 divides 486)
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