net force=weight down hill - friction
weight down hill=mgSinTheta
friction=mg*mu*cosTheta
Netforce=mass* acceleration
solve for acceleration.
A 61-kg person on skis is going down a hill sloped at 30¡Æ from the horizontal. The coefficient of friction between the skis and the snow is 0.16. What would be the magnitude of the acceleration?
An crate weighing 576 N is resting on a plane inclined 29¡Æ above the horizontal. The magnitude of the acceleration (ignore friction) is1 m/s2.
After 5.00 s, how fast will the crate be moving?
3 answers
I got the answer! Thank you! Can you help me with the second problem please?
GOD
2 answers