A 69 kg person on skis is going down a hill sloped at 36° below the horizontal (+x direction). The coefficient of friction between the skis and the snow is 0.15. Find the x and y components of the weight of the skier going downhill.

Answer 1

Ws = mg = 69 kg * 9.8 N/kg = 676.2 N. =
Weigth of skier.
Fs = 676.2 N. @ 36 deg.=Force of skier.
Fp = X = 676.2*sin36 = 397.5 N. = Force parallel to hill.
Fv = Y = 676.2*cos36 = 547.1 N. = Force
perpendicular to hill.

Answer 2

hhsh