sqrt(Fx^2+Fy^2)
tan A = Fy/Fx
A crate is pulled to the right with a force of 80 N, to the left with a force of 125.8 N, upward with a force of 615.4 N, and downward with a force of 248 N.
Net external force in the x direction:
-45.8
Net external force in the y direction: 367.4 N
how do i find the magnitude of the net
external force on the object?
also...
What is the direction of the net external force on the crate (as an angle between −180◦ and 180◦, measured from the positive x axis with
counterclockwise positive)?
2 answers
i got the magnitude i still don't get tan A = Fy/Fx
can you explain thoroughly?
can you explain thoroughly?
3 answers