The object located between F and 2F => the image will be located beyond the 2F point on the other side of the lens. It is real, inverted and its dimension is larger than the object demension.
d₀ - object distance
d₁ - image distance
f- focal lenth
1/d₀ +1/d₁ =1/f
1/d₁ =1/f - 1/d₀ =
= (d₀-f)/ d₀•f
d₁=d₀•f/(d₀-f)=0.04•0.025/(0.04-0.025) = 0.067 m
h₀/d₀=h₁/d₁
h₁= d₁•h₀/d₀=0.067•0.04/0.04 = 0.067 m
A convex lens of focal length 2.5 cm is placed 4 cm from a small object of height 4 cm. Use a ruler and construct the image. Is the image real or virtual, upright or inverted? What is the image distance? What is the height of the image? What is the magnification?
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