A converging lens has a focal length of 0.060 m. An object is located 0.020 m to the left of this lens. A second converging lens has the same focal length as the first one and is located 0.100 m to the right of it. Relative to the second lens, where is the final image located?

Answer 1

The image formed by the first lens is virtual, and is located at X given by
1/0.02 + 1/X = 1/0.06
1/X = -33.33
X = -0.03
The minus sign indicates it is 0.03 m to the LEFT of lens 1. That becomes the object position for the second lens, and it is 0.13 m to the left of lens 2. For the location of the final image, solve
1/0.13 + 1/Di = 1/0.06
Do is the image distance, measured to the right of lens 2.