A container of water is knocked off a 10.00–meter–high ledge with a horizontal velocity of 1.00 meters/second. Calculate the time it takes for the container to reach the ground.
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distance = 1/2*g*t^2. You know distance and g (9.8 m/s^2). Solve for time. Note that the horizontal velocity has nothing to do with the problem. The horizontal velocity determines how far horizontally from the ledge it lands and not how long it takes to reach the ground.
1 answer