I do not see the figure but am at a loss to understand how the ledge has anything to do with it unless he hits it.
u = 17 m/s until splash
Vi = 0
h = 7.9 m
h = 4.9 t^2
so
t = 1.27 seconds
v = 9.81 t = 9.81*1.27 = 12.5 m/s
speed = sqrt (17^2 + 12.5^2)
A stunt car driver drives off an
h = 7.9 m-high cliff into a lake with a horizontal speed of 17 m/s. The car needs to clear an 17.1 m-long ledge that is 5.0 m below the edge of the cliff, as shown in the figure below. The car just misses the ledge on the way down. With what speed does the car hit the water?
1 answer
1 answer