Question

A construction company orders tile flooring for the kitchen and three bathrooms of a new home. The kitchen floor measures 48 square feet. Two bathrooms have floors that each measure 30 1/2 square feet. The third bathroom floor measures 42 1/2 square feet. If the tile cost 2.39 per square foot, what is the least amount of money, to the nearest cent, the company spends on tile for all three bathrooms?

Answer 1

To find the total cost for the tile flooring for the kitchen and three bathrooms, we first need to calculate the total area that requires tile.

1. Calculate the total area of the kitchen: \[ \text{Area of kitchen} = 48 \text{ square feet} \]

2. Calculate the total area of the two bathrooms that each measure 30.5 square feet: \[ \text{Area of two bathrooms} = 2 \times 30.5 = 61 \text{ square feet} \]

3. Calculate the area of the third bathroom: \[ \text{Area of third bathroom} = 42.5 \text{ square feet} \]

4. Now, sum all the areas: \[ \text{Total Area} = \text{Area of kitchen} + \text{Area of two bathrooms} + \text{Area of third bathroom} \] \[ \text{Total Area} = 48 + 61 + 42.5 = 151.5 \text{ square feet} \]

Next, we need to find out how much the tile will cost.

5. Since the cost of the tile is $2.39 per square foot, we calculate the total cost: \[ \text{Total Cost} = \text{Total Area} \times \text{Cost per square foot} \] \[ \text{Total Cost} = 151.5 \times 2.39 \]

6. Performing the multiplication: \[ 151.5 \times 2.39 = 362.085 \]

7. To find the total cost to the nearest cent, we round $362.085 to: \[ \text{Total Cost (to the nearest cent)} = 362.09 \]

Thus, the least amount of money the company spends on tile for all areas is: \[ \boxed{362.09} \]