A construction company orders tile flooring for the kitchen and three bathrooms of a new home. The kitchen floor measures for 8 ft.². Two bathrooms have floors that measure 31/2 square ft.². The third bathroom floor measures 42 1/2 square feet. Tile cost 239 per square foot. What is the least amount of money to the nearest cent the company spends on tile for all three bathrooms

1 answer

To find the total cost of the tile flooring for the kitchen and three bathrooms, we will first calculate the total area of tile needed for all the spaces and then multiply that by the cost per square foot of the tile.

  1. Calculate the area for the kitchen: \[ \text{Area of kitchen} = 8 \text{ ft}^2 \]

  2. Calculate the area for the two bathrooms: Each of the two bathrooms has an area of \(3.5 \text{ ft}^2\): \[ \text{Total area of two bathrooms} = 2 \times 3.5 \text{ ft}^2 = 7 \text{ ft}^2 \]

  3. Calculate the area for the third bathroom: \[ \text{Area of third bathroom} = 42.5 \text{ ft}^2 \]

  4. Calculate the total area: \[ \text{Total area} = \text{Area of kitchen} + \text{Total area of two bathrooms} + \text{Area of third bathroom} \] \[ \text{Total area} = 8 \text{ ft}^2 + 7 \text{ ft}^2 + 42.5 \text{ ft}^2 = 57.5 \text{ ft}^2 \]

  5. Calculate the total cost: Cost per square foot is $2.39. Therefore: \[ \text{Total cost} = \text{Total area} \times \text{Cost per square foot} \] \[ \text{Total cost} = 57.5 \text{ ft}^2 \times 2.39 \text{ dollars/ft}^2 \] \[ \text{Total cost} = 137.825 \text{ dollars} \]

Rounding this to the nearest cent: \[ \text{Total cost} = 137.83 \]

Thus, the least amount of money the company spends on tile for all three bathrooms and the kitchen is $137.83.