well, the energy given to the stone in kinetic motion is net force*distance or
KE=(390-31)*2 and that is equal to the change in PE that will happen, mgh
mgh=(359*2 solve for h.
A constant net force of 390 N is applied upward to a stone that weighs 31 N. The upward force is applied through a distance of 2.0 m, and the stone is then released. To what height, from the point of release, will the stone rise? Assume that air resistance is negligible.
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