Question

A concentrated solution of ammonia is added to a solution of zinc oxide?
NH3 + ZnI2 => ??

An excess of nitric acid solution is added to a solution of tetraaminecopper (II) sulfate.
HNO3 + ? => ??

Zn forms the Zn(NH3)4^+2 ion. It MAY form some Zn(OH)2 at small amounts of NH3(aq) but I think all will eventually end up as the complex ion.
Cu(NH3)4SO4 + HNO3 ==> neutralizes the NH3.

what would the products be though, not just the NIE

I don't know how to answer the Zn part because ZnO is not soluble in water. So what it the ZnO solution a solution in??
And there will not be a molecular equation if there is no ppt. Anyway, at first, Zn(OH)2 forms and that is soluble in an excess of NH3.
Zn^+2 + 2NH3 + 2H2O ==> Zn(OH)2 + 2NH4^+
then an excess of NH3:
Zn(OH)2 + 4NH3 ==> Zn(NH3)4^+2 + 2OH^-

Cu(NH3)4SO4 + 4HNO3 ==> Cu^+2 + 4NH4^+ + SO4^= + 4NO3^-

Check my work.