Asked by Freddy
A concentrated solution of sulphuric (VI) acid contains 72.5% sulphuric (VI) acid. If the density of the acid is 1.8g/cm3 determine the molarity of the acid solution. (H= 1, O=16, S = 32)
Answers
Answered by
DrBob222
density = 1.8 g/mL.
mass 1000 mL = 1.8 g/mL x 1000 mL = ?
mass H2SO4 in the 1000 = mass of the 1000 mL x 0.725 = ?
Then M = mass H2SO4/98 g/mol = ?. Put it together like this.
1.8 g/mL x 1000 mL x 0.725 x 1/98 = ?M
mass 1000 mL = 1.8 g/mL x 1000 mL = ?
mass H2SO4 in the 1000 = mass of the 1000 mL x 0.725 = ?
Then M = mass H2SO4/98 g/mol = ?. Put it together like this.
1.8 g/mL x 1000 mL x 0.725 x 1/98 = ?M
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