a) Let's say the number of cars sold by Dealership A is C, and the number of trucks sold by Dealership A is T. Therefore, the equation for the total cars and trucks for Dealership A is:
C + T = 164
b) Let's say the number of cars sold by Dealership B is C', and the number of trucks sold by Dealership B is T'. Therefore, the equation for the total cars and trucks for Dealership B is:
C' + T' = 229
c) From the equation in part a), we know that C + T = 164. Since Dealership B sells twice as many cars as Dealership A, we can say C' = 2C. Substituting this into the equation, we get:
2C + T = 164
Now, we can substitute T = 164 - C into the equation for the total cars and trucks for Dealership B:
C' + T' = 229
2C + T' = 229
Since Dealership B sells half as many trucks as Dealership A, we can say T' = (1/2)T. Substituting T = 164 - C, we get:
2C + (1/2)(164 - C) = 229
2C + 82 - (1/2)C = 229
(3/2)C = 147
C = 98
Therefore, Dealership A sold 98 cars.
d) Substituting C = 98 into the equation T = 164 - C, we get:
T = 164 - 98
T = 66
Therefore, Dealership A sold 66 trucks.
A company owns two dealerships, both of which sell cars and trucks. Dealership A sells a total of 164 cars and trucks. Dealership B sells twice as many cars and half as many trucks as Dealership A, and sells a total of 229 cars and trucks.
a) An equation for the total cars and trucks for Dealership A:
b) An equation for the total cars and trucks for Dealership B:
c) How many cars did Dealership A sell?
d) Considering that Dealership B sold half as many trucks as Dealership A, how many trucks did Dealership B sell?
1 answer
1 answer