Let's represent the number of cars sold by Dealership A as "Ca" and the number of trucks as "Ta".
We know that Ca + Ta = 164.
Let's represent the number of cars sold by Dealership B as "Cb" and the number of trucks as "Tb".
We know that Cb + Tb = 229.
We also know that Cb = 2(Ca) and Tb = 0.5(Ta).
Substituting Cb = 2(Ca) into Cb + Tb = 229, we get 2(Ca) + Tb = 229.
Substituting Tb = 0.5(Ta) into 2(Ca) + Tb = 229, we get 2(Ca) + 0.5(Ta) = 229.
Multiplying through by 2 to remove the decimal, we get 4(Ca) + Ta = 458.
Substituting Ca + Ta = 164 into 4(Ca) + Ta = 458, we get 4(Ca) + 164 = 458.
Subtracting 164 from both sides, we get 4(Ca) = 458 - 164 = 294.
Dividing both sides by 4, we get Ca = 294/4 = 73.
Therefore, Dealership A sold 73 cars.
Since Tb = 0.5(Ta), and Ta = 164 - Ca = 164 - 73 = 91, we can substitute into the equation Tb = 0.5(Ta).
Therefore, Tb = 0.5(91) = 45.
Therefore, Dealership B sold 45 trucks.
A company owns two dealerships, both of which sell cars and trucks. Dealership A sells a total of 164 cars and trucks. Dealership B sells twice as many cars and half as many trucks as Dealership A, and sells a total of 229 cars and trucks. (4 points) How many cars did Dealership A sell? d) Considering that Dealership B sold half as many trucks as Dealership A, how many trucks did Dealership B sell?
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