A company owns two dealerships, both of which sell cars and trucks. Dealership A sells a total of 164 cars and trucks. Dealership B sells twice as many cars and half as many trucks as Dealership A, and sells a total of 229 cars and trucks. %0D%0A%0D%0A(4 points)%0D%0Aa) An equation for the total cars and trucks for Dealership A: %0D%0A%0D%0Ab) An equation for the total cars and trucks for Dealership B: %0D%0A%0D%0Ac) How many cars did Dealership A sell? %0D%0A%0D%0Ad) Considering that Dealership B sold half as many trucks as Dealership A, how many trucks did Dealership B sell?

Answer 1

a) Let's assume the number of cars sold by Dealership A is C1 and the number of trucks sold by Dealership A is T1. Therefore, the equation for the total cars and trucks sold by Dealership A can be written as:
C1 + T1 = 164

b) Let's assume the number of cars sold by Dealership B is C2 and the number of trucks sold by Dealership B is T2. According to the given information, Dealership B sells twice as many cars as Dealership A and half as many trucks as Dealership A. Therefore, the equation for the total cars and trucks sold by Dealership B can be written as:
C2 + T2 = 229

c) From the equation in part a), we know that C1 + T1 = 164. To find the number of cars sold by Dealership A, we need to isolate C1. This can be done by subtracting T1 from both sides of the equation:
C1 = 164 - T1

d) According to the given information, Dealership B sold half as many trucks as Dealership A. Therefore, T2 can be expressed as T1/2. We can substitute this value in the equation from part b) to find the number of trucks sold by Dealership B:
C2 + T1/2 = 229.