A company is considering offering child care for their employees. They wish to

estimate the mean weekly child-care cost of their employees. A sample of 10 employees
reveals the following amounts spent last week in dollars.



107 92 97 95 105 101 91 99 95 104



Develop a 90% confidence interval for the population mean. Interpret the result.

=??, S=??, =??, Range of = (??) xt2/.
.

3 answers

Find the mean first = sum of scores/number of scores

Subtract each of the scores from the mean and square each difference. Find the sum of these squares. Divide that by the number of scores to get variance.

Standard deviation (SD) = square root of variance

Range = highest score - lowest

90% interval = mean ± 1.645SD

I'll let you do the calculations.
5s1a
company is considering offering child care for their employees. They wish to
estimate the mean weekly child-care cost of their employees. A sample of 10 employees
reveals the following amounts spent last week in dollars.