16099.44 = 15000(1+i)^2
1.073296 = (1+i)^2
1+i = √1.073... = 1.036
i = .036 or 3.6%
A company invests $15,000.00 in an account that compounds interest annually. After two years, the account is worth $16,099.44. Use the function in which r is the annual interest rate, P is the principal, and A is the amount of money after t years. What is the interest rate of the account? A = P(1 + r)t
A.) 1.04%
*B.) 3.6%
C.) 5.4%
D.) 7.3%
Thanks.
13 answers
the answers for the quiz to my fellow 2017,2018,2019, whenever ur reading this are
1) solve for t.
d-49
2) solve for g.
a-5
3) solve for d.
d- 6, -6
4) which is the extraneous solution of
d-5
and this problem, which is b)3.6%
1) solve for t.
d-49
2) solve for g.
a-5
3) solve for d.
d- 6, -6
4) which is the extraneous solution of
d-5
and this problem, which is b)3.6%
they're correct^
Instead of -5 it's just 5 for number 4 I just took the test for connexus.
DADDB is correct for Lesson 4: Solving Radical Equations
D
A
A
B
B
A
A
B
B
dingdong is right
Read my name
^ 6 is false :D
1. 49
2. 5
3. 6, -6
4. 5
5. 3.6%
6. False
Your Welcome :)
2. 5
3. 6, -6
4. 5
5. 3.6%
6. False
Your Welcome :)
... is correct!! POGGERS!!
thanks for the help "..." I got 100%
You're welcome! Have a great day!