A committee of 4 people is to be chosen from 5 married coiples.find in how many ways the committee can be chosen if:

Question

i) everyone is equallt eligible
ii) the committee should include at least one woman
solution so far.5 couples=10 people.
To choose 4=10C4=10!/(10-4)!4!=210 ways.pls help confirm if i am correct and also help solve (ii)

Answer 1

i) 210 is correct

ii) So what we don't want is to have all-men committees

number of all men committees = C(5,4) = 5

so the number with at least one woman
= 210 - 5 = 205