From a group of 10 people, 5 men and 5 women, six are to be chosen to serve on a committee.

Question

a) In how many ways can the committee be chosen?
b) Find the probability that two men will be chosen.
c) Find the probability that the committee chosen will consist at least 4 women.

Answer 1

number of ways to choose 6 from 10
= C(10,6) = 1056

b) number with 2 men and 4 women
= C(5,2) x C(5,4)
= 10(4) = 40
prob(choosing 2men and 4 women) = 40/1056
= 5/132

c) at least 4 women --> 4 women or 5 women
= C(5,4)C(5,2) + C(5,5)C(5,1)
= 5(40) + 1(5)
= 205
prob(at least 4 women) = 205/1056

Answer 2

the committee can be chosen in these different ways

4b 2g and it6 can also be
4g 2b in many other ways!!!
6b 0g
6g ob
3b 3g
5g 1b
5b 1b

Answer 3

if what i posted wasn't your question sorry cause after i submited that i started thinking that it wasnt..........