Asked by aritro

A coin of mass 3 g slides horizontally on the surface of a table. The frictional force exerted on the penny is 0.0147 N. What is the coefficient of friction between the table and the penny?
Answered by Devron
0.0147=Fn(µk)= (3kg)(9.8m/s^2)µk,

Solve for µk
Answered by drwls
0.0147 = 0.003*g*(µk)

µk = 0.50

Devron forgot to convert mass to kg.
Answered by Devron
Read it wrong. Thought mass was already given in Kg
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