0.0147=Fn(µk)= (3kg)(9.8m/s^2)µk,
Solve for µk
A coin of mass 3 g slides horizontally on the surface of a table. The frictional force exerted on the penny is 0.0147 N. What is the coefficient of friction between the table and the penny?
3 answers
0.0147 = 0.003*g*(µk)
µk = 0.50
Devron forgot to convert mass to kg.
µk = 0.50
Devron forgot to convert mass to kg.
Read it wrong. Thought mass was already given in Kg