A closed container has a mixture of methane, CH4, ethane C2H6, and propane C3H8. If 12.5 g of methane, 36.0 g of ethane, and 14.0 g of propane have a total pressure of 890. mm Hg, what is the partial pressure of each of the gases in the container?

Answer 1

Convert grams each gas to mols.
mols = g/molar mass

Convert each gas to mole fraction.
Xeach gas = mol each gas/total mols.

partial pressure each gas = Xeach gas*Ptotal