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A clock has a second hand whose tip rubs against the inside of the glass cover. If the frictional force between the glass cover...Asked by Max
A clock has a second hand whose tip rubs against the inside of the glass cover. If the frictional force between the glass cover and the tip of the second hand is 0.0010 N and the length of the hand is 6.5 cm, what is the minimum torque that must be applied to the second hand if the clock is not to be stopped?
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Answered by
Damon
.001 * .065 Nm
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