Asked by KC
A class has 12 students. In how many different ways can the students be put into lab groups consisting of 3 students in each group.
The answer in the book is 369600. But I do not understand how they got this answer.
The answer in the book is 369600. But I do not understand how they got this answer.
Answers
Answered by
MathMate
The number of ways groups of m and (n-m) objects that can be formed from n distinct objects is
n!/(m!(n-m)!)
The analogous formula for groups each consisting of m1, m2, m3...mt objects (which add up to n) is:
n!/(m1!m2!m3!....mt!), where m1+m2+m3...mt = n.
Thus the number of ways of partitioning 12 students into 4 groups of 3 is 12!/(3!3!3!3!)
= 369600
n!/(m!(n-m)!)
The analogous formula for groups each consisting of m1, m2, m3...mt objects (which add up to n) is:
n!/(m1!m2!m3!....mt!), where m1+m2+m3...mt = n.
Thus the number of ways of partitioning 12 students into 4 groups of 3 is 12!/(3!3!3!3!)
= 369600
Answered by
keke
i don not no well the calclus is the same kinda so you should probally choose division yeah division
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