There are 10 students in a class. The teacher chooses 3 students to go to the library. The order in which they are chosen does not matter. How many ways are there to choose the students?

Since the order in which the students are chosen does not matter, we can use combinations to solve this problem. The number of ways to choose 3 students out of 10 is given by the combination formula:

${{10}\choose{3}}=\frac{10!}{3!(10-3)!}=\frac{10!}{3!7!}=\frac{10\times9\times8}{3\times2\times1}=120$.

Therefore, there are $\boxed{120}$ ways to choose the students.