A circular surface with a radius of 0.058 m is exposed to a uniform external electric field of magnitude 1.49 104 N/C. The electric flux through the surface is 74 N · m2/C. What is the angle between the direction of the electric field and the normal to the surface?

Question

A circular surface with a radius of 0.058 m is exposed to a uniform external electric field of magnitude 1.49  104 N/C. The electric flux through the surface is 74 N · m2/C. What is the angle between the direction of the electric field and the normal to the surface?

bobpursley · Answer

E normal=74*area arccosTheta=Enormal/Eexternal