A Chinook salmon can jump out of water with a speed of 6.60 m/s . How far horizontally d can a Chinook salmon travel through the air if it leaves the water with an initial angle of θ=27.0° with respect to the horizontal? (Let the horizontal direction the fish travels be in the +x direction, and let the upward vertical direction be the +y direction. Neglect any effects due to air resistance.)

1 answer

Range=[6.60m/s*Sin(2*25)]/9.8m/s^2=distance traveled in the x direction