A child bounces a 46 g superball on the side-walk. The velocity change of the superball isfrom 28 m/s downward to 16 m/s upward.If the contact time with the sidewalk is1800s, what is the magnitude of the average forceexerted on the superball by the sidewalk?

Question

Answer in units of N.

Answer 1

force*time= mass*changevelocity
= mass*(16-(-28)

find force.

Answer 2

i got 1.124 nd it said it was wrong

force*1800s=46*44
force*1800s=2024
force=1.12444444

Answer 3

The problem with your answe was that you didn't convert the grams to kg

Answer 4

Also it's not 1800, it's 1/800

Answer 5

Also it's not 1800, it's 1/800
so it would be: .046kg * 44 = 2.024
2.024/(1/800)

It should equal = 1619.2
Check your answer but that should be it, especially if they're asking you in units of N