A child bounces a 55 g superball on the side-

Question

walk. The velocity change of the superball is
from 22 m/s downward to 14 m/s upward.
If the contact time with the sidewalk is
1
800
s, what is the magnitude of the average force
exerted on the superball by the sidewalk? Answer in units of N

Answer 1

change velocity (Vf-Vi)= (14-(-22)=36m/s upward

force*timecontact= mass*changevelocity

solve for force.

Answer 2

yes