A chemist wants to make 5.5 L of a 0.250 M CaCl2 solution, what mass of CaCl2 (in g) should the chemist use?

Answer 1

massCaCL2=molarity*volume*molmassCaCl2

Answer 2

Wha??

Answer 3

M = 0.250 mols/L * (111g CaCl2/1 mols CaCl2)= 27.7g/L
n = M*L
n = (27.7g/L)*(5.5L)= 153g of CaCl2