A chemist wants to make 4.5 L of a 0.310 M CaCl2 solution what mass of CaCl2 (in g) should the chemist use

3 answers

How many moles do you want?
moles = M x L = ??
Then moles = grams/molar mass
Solve for grams.
.310*4.5*82.96
115.7