it is being diluted 81/9 times , or 9 times.
that means one part original solution, and 8 parts water.
one part stock= 500/9 ml= ...
eight parts water= 8*500/9 = ...
A chemist must prepare 500 ml of 9.00uM aqueous mercury(II) iodide working solution. He'll do this by pouring out some 81.0 umol/L aqueous mercury(II) iodide stock solution into a graduated cylinder and diluting it with distilled water.
Calculate the volume in of the mercury(II) iodide stock solution that the chemist should pour out. Be sure your answer has the correct number of significant digits.
2 answers
Good job, but how many significant figures should be recorded in the answer?
1 answer