To calculate the concentration of the mercury(II) iodide solution, we first need to calculate the number of moles of HgI2 present in the solution.
Molar mass of HgI2:
Hg = 200.59 g/mol
I = 126.90 g/mol
HgI2 = 200.59 g/mol + 2(126.90 g/mol) = 454.39 g/mol
Number of moles of HgI2 = 0.011 g / 454.39 g/mol = 2.42 x 10^-5 mol
Now, we need to calculate the volume of the solution in liters:
250. ml = 250. x 10^-3 L = 0.250 L
Concentration of HgI2 = number of moles / volume of solution
Concentration = 2.42 x 10^-5 mol / 0.250 L = 9.68 x 10^-5 mol/L
Therefore, the concentration of the chemist's mercury(II) iodide solution is 9.68 x 10^-5 mol/L.
A chemist prepares a solution of mercuryII) iodide (Hgi, by measuring out 0.011 g of mercuryIl) iodide into a 250. mi volumetric flask and filling the flask to the mark with water.
Calculate the concentration in mol/L of the chemist's mercury(II) iodide solution. Be sure your answer has the correct number of significant digits.
1 answer