A chemist dissolves 0.096 g of CuSO4 · 5 H2O in water and dilutes the solution to the mark in a 500-mL volumetric flask. A 10.8-mL sample of this solution is then transferred to a second 500-mL volumetric flask and diluted. What is the molarity of CuSO4 in the second solution?

Question

My Work:
Mass of CuSO4.5H2O per mL = 0.096/500g
mass in 43.6mL = 0.096/500 x 10.8 g = 0.0083712

That is put into 500mL for second flask, so mass per liter = 0.096/500 x 10.8 x 2g

To find molarity, divide by molar mass = 0.096/500 x 10.8 x 2/249.7 M

Answer 1

moles CuSO4.5H20=.096/250

moles transfered: 10.8/.500*.096/250
molarity second solultion:
10.8/.500*.096/250*1/.5

check that, it is not the same as your solution