A chemist dissolves 0.091 g of CuSO4 · 5 H2O

Question

in water and dilutes the solution to the mark
in a 500-mL volumetric flask. A 31.8-mL
sample of this solution is then transferred to a
second 500-mL volumetric flask and diluted.
What is the molarity of CuSO4 in the second
solution?

Answer 1

0.091g of CuSO4 *(mole/159.609 g)=moles

Moles/0.5L=M1

M1*(31.8ml)=M2*(500mL)

Some for M2:

M2=M1*[(31.8ml)/(500mL)]