A charge of -6.17 μC is traveling at a speed of 5.47 × 106 m/s in a region of space where there is a magnetic field. The angle between the velocity of the charge and the field is 53.2o. A force of magnitude5.37 × 10-3 N acts on the charge. What is the magnitude of the magnetic field?

Answer 1

http://hyperphysics.phy-astr.gsu.edu/hbase/magnetic/movchg.html

F = Q * V x B
F = -6.17*10-6 * 5.57*10^6 * sin 53.2 * B
5.37*10^-3 = | -6.17*10-6 * 5.57*10^6 * sin 53.2 * B |
so
|B| = 5.37*10^-3 / (6.17 * 5.57 * sin 53.2)