A poorly worded question. No amount of electricity will deposit AgNO3 solution. It will deposit Ag (metal) but not AgNO3 solution.
96,485 Coulombs will deposit 107.9 g Ag. How many C were involved? That's
96,485 x (0.54/107.9) = ?
That will liberate 1 g H2. Convert 1 g H2 to mols and use PV = nRT to convert to L at the conditions listed.
A certain quantity of electricity deposits 0.54grams of silver nitrate solution. What volume of H2 will be liberated by the same quantity of electricity at 27 ° C and 750 mm of Hg pressure
1 answer
1 answer