Calculate the volume in milliliters of a 3.39M silver nitrate solution that contains 75.0 g of silver nitrate (AgNO3) Be sure your answer has the correct number of significant digits.

Answer 1

To calculate the volume of the solution, first we need to find the molar mass of AgNO3:

Ag: 107.87 g/mol
N: 14.01 g/mol
O: 16.00 g/mol
Total molar mass = 107.87 + 14.01 + (3 * 16) = 169.88 g/mol

Next, we will use the formula for molarity:

Molarity = moles of solute / volume of solution in liters

Rearranging for volume of solution, we get:

Volume = moles of solute / molarity

First, we need to find the moles of AgNO3 in 75.0 g:

moles = mass / molar mass = 75.0 g / 169.88 g/mol = 0.4414 moles

Now we can calculate the volume of the solution:

Volume = 0.4414 moles / 3.39 mol/L = 0.130 L = 130 mL

Therefore, the volume of the 3.39M silver nitrate solution that contains 75.0 g of AgNO3 is 130 mL.