Fe+2HCl>>FeCl2?+H2
so moles of H2=44.8/22.4=2 moles, which then idicates 2/.8 moles of Fe
m=(2/.8) * mole mass Fe
mass HCl= (4/.8)*molemassHCl
A certain mass(m) of an impure iron sample of 40% purity ,is treated with an excess of HCl to give H2 that occupies 44.8 L at s.t.p ( Vm=22.4) where the yeild of the reaction is 0.8.
A) calculate m.
B) deduce the mass of HCl reacted.
Thanks in advance!!
1 answer
2 answers