8.5g of sample of iron required just 75cm3 of 3.00M HCl to dissolve it and give a neutral solution.Calculate the percentage purity of the sample of iron.

Answer 1

Fe + 2HCl ==> FeCl2 + H2
mols HCl = M x L = ?
mols Fe = 1/2 that (from the coefficients in the balanced equation)
g Fe = mols Fe x atomic mass Fe
%Fe or %purity = (g Fe/mass sample)*100 = ?
However, I don't buy your "throwaway statement" that FeCl2 solution is a neutral solution. I would bet money that it is acidic.

Answer 2

Percentage purity of sample iron 74.12%