a certain force acting on a body of mass 2 kg increases it's velocity from 6m/s to 15m/s in 2 seconds . the work done by the force during this interval is ?

2 answers

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Sra
W = Fd
F = ma

a = (15-6)/2 = 4.5
d = 1/2 at^2 = 2.25*4 = 9

W = 2*4.5*9 = 81