force applied is 200N, what is the spring constant of the catapult?
The formula for Hooke's Law is F = kx, where F is the force, k is the spring constant, and x is the displacement.
First, we need to convert the mass of the stone from grams to kilograms:
mass (kg) = mass (g) / 1000 = 500g / 1000 = 0.5kg
Next, we need to convert the extension length from centimeters to meters:
extension (m) = extension (cm) / 100 = 20cm / 100 = 0.2m
We can plug in the values we have into Hooke's Law formula and solve for the spring constant:
200N = k * 0.2m
Dividing both sides of the equation by 0.2m:
k = 200N / 0.2m = 1000 N/m
Therefore, the spring constant of the catapult is 1000 N/m.
A catapult used to hold a stone of mass 500g is
extended by 20cm with an applied force f. If the
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