V=4πR³/3
Density ρ=m/V = 3m/4πR³ = >
R=cuberoot(3m/4π ρ)
the gravitational constant
G =6.67•10^-11 N•m²/kg²,
F =G•m1•m2/R²
A carefully designed experiment can measure the gravitational force between masses of 6 kg. Given that the density of iron is 7860 kg/m3, what is the gravitational force between two 6.00-kg iron spheres that are touching?
The answer is 1.87e-07 N. How do I get this answer?
4 answers
Sorry! Force is
F =G•m1•m2/(2R)²
F =G•m1•m2/(2R)²
Thank you!
How do you figure out the R-value?
0 answers