a = change in velocity/change in time
= 44/5 = 8.8 ft/s^2
a = same formula = (88-44)/4 = 11 ft/s^2
a = (66 -88)/3 = -7.33 ft/s^2
sum of a*t / total t
(8.8*5 + 11*4 - 7.33*3)/12
= 5.5 m/s^2
a car travels on a straight road.
a) starting from rest, the car is going 44 ft/s (30 mi/h) at the end of 5.0 s. What is the car's average acceleration in ft/s^2
b) in 4.0 more seconds, the car is going 88 ft/s (60 mi/h). what is the car's average acceleration for this time period?
c) the car then slows to 66 ft/s (45 mi/h) in 3.0 s. what is the average acceleration for this time period?
d) what is the overall average acceleration for the total time?
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How to solve
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