A car travels 2.06 km in the x-direction, then
turns left 70.3 degrees to the original direction and
travels an additional distance of 4.23 km.
Calculate the x component of the car’s net
displacement.
Let :
d1 = 2.06 km,
theta = 70.3 degrees , and
d2 = 4.23 km.
1 answer
3.2485912943 km