A car traveling at 10 m/s accelerates at 2.03 m/s2 for 11 seconds. To the nearest meter how far does it travel?

Question

To the nearest tenth of a m/s, what is the final velocity of the car in the previous problem?

Answer 1

Use the appropriate formulas.

X = (1/2) a t^2 + Vo*t

V = Vo + a*t

Vo is the initial velocity, 10 m/s
t = 11 s
a = 2.03 m/s^2