A car tire contains air at a pressure of 24 lb/in^2 at 0 degrees C. If the volume of the tire remains unchanged, what will the pressure be when the temperature has increased to 32 degrees C?

Answer 1

Charles' law, P1/T1=P2/T2, or P/T=constant, as long as volume is constant. T must be in °K.

24/(273.15+0)=P/(273.15+32)
Solve for P
P=24/(273.15)*(305.15)
=26.8 lb/in²

Answer 2

It's Gay-Lussac's Law, not Charles' law (T vs V).