a car starts from rest at constant acceleration of 2m/s2 at the same instant, a truck travelling at a constant speed of 10m/s overtakes and passes the car

Question

a car starts from rest at constant acceleration of 2m/s2 at the same instant, a truck travelling at a constant speed of 10m/s overtakes and passes the car 
i) how far beyond the starting point will the car overtake the truck
ii) after what time will this happen
iii) at what instant will be the speed of the car

Joel · Accepted Answer

I want all the answers by showing all working out. Stpe by step accordingly.

bobpursley · Answer

They both travel the same distance, in the same time. truck: distance=10t car: distance=1/2 2 t^2 10t=t^2 10=t so time is ten seconds. distance=10*t velocitycar=2*t=20m/s

Anonymous · Answer

2.5m/s

anonymous · Answer

the answer is 20m/s

Umesh · Answer

Good

Sarita · Answer

Equation of motion for he truck: s=ut Equation of motion for the car: s=1/2at^2 the second solution gives , s=2u^2/a = 2*10^2/2 = 100m

Lena · Answer

180 m from stoplight at t=12 s

David · Answer

Full calculation

David · Answer

Full calculation of the problem

Joel · Answer

Want all answers step by step working outs

Graffy · Answer

1 want working out for the answer

Junior · Answer

Solving the problem stap by stap calculation please?

Visiion Kipandu · Answer

Please show step by step

Gerry · Answer

Please show all calculations step by step

Habtamu Tadesse · Answer

thats good✍️

Anonymous · Answer

please im begging u